Question

If a cube of maximum possible volume is cut off from a solid sphere of diameter d, then the volume of the remaining (waste) material of the sphere would be equal to:
A) d33(π−d2)
B) d33(π2−1√3)
C) d24(√2−π)
D) None of these

Answer 1

Option C

Plz mark me as the brainliest.

If it’s correct.

Answer 2

Answer:

Step-by-step explanation:

Let the side of the given cube be 'a'

Therefore,

Diagonal of the cube = √3a²

= a√3

Now, according to the question,

a√3 = d

a = d/√3

Volume of the sphere = 4/3 × π × (d/2)³

= 4/3 × π × d³/8

= (1πd³)/6

Volume of the cube = a³ = (d/√3)³

= d³/3√3

Volume of the remaining waste material = (1πd³)/6 - (d³/3√3)

= d³(1π/6 - 1/3√3)