if a cube plus b cube plus c cube - 3abc
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Answer:
a+b=-c
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Answer:
x + y + z = 0
Step-by-step explanation:
we know that x^3 + y^3 + z^3 - 3xyz = (1/2)(x+y+z)[(x-y)^2 + (y-z)^2 + (z-x)^2]
then put x + y + z = 0 and get x^3 + y^3 + z^3 - 3xyz = 0 or x^3 + y^3 + z^3 = 3xyz
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