Question

If a curren of 1.5 a is maintaned in a resistor of 10 ohm, then the energy dissipated in the resister in 1 minuter is

Answer 1

Answer is 1.35kj . Hope it will help you.

Answer 2

$\textbf{ANSWER}$

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$\textbf{GIVEN}$

Current =1.5 A

Resistance = 10ohm

Time = 1minute =60second

$\textbf{REQUIRED}$

Energy dissipated = ?

$\textbf{FORMULA}$

Energy dissipation = E= Pt

$\textbf{SOLUTION}$

We know that power is given by

P= I^2R

So

E = I^2Rt

E= (1.5)^2 × 10 × 60

E=1350 J

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