Question

if a current 3.2 ampere per second flows through a conducting wire calculate the number of electron passing through a wire​

Answer 1

2×10^19

Explanation:

n=It/e

=3.2×1/1.6×10^-19

=2×10^19

Answer 2

Answer:

Number of electron=$2\times10^{19}$

Explanation:

since it is given that a current 3.2 ampere per second flows through a conducting wire.we need to find the number of electron passing through a wire​.

we know that

quantanisation of charge gives q=ne.....................(1)

where q=charge, n=number of electrons, e=charge on electron.

we know the definition of current i.e. i=$\frac{q}{t}$.....................(2)

from (1) and (2)

we get

i=$\frac{ne}{t}$..................(3)

since i=3.2amp

$e=1.6\times10^{-19}$

t=1sec

put all the values in (3)

$3.2=\frac{n\times1.6\times10^{-19} }{1}$

after solving we get

$n=2\times10^{19}$ which is the required number of electrons.