Question

if a current of 0.5 amp flows through a wire for 2 hours then how many electrons would flow trough wire ? ​

Answer 1

Answer:

Using,

q = it

Where,

q is the charge flown in that wire in that given time!!

t is the time

i is the Current in Wire

So,

q = 0.5*(2*60*60)

q = 3600 C

Now Using Charge Quantization

q = ne

Where,

q is the magnitude of charge  

n is the number of electrons

e is the magnitude of electron

3600 = n*(1.6*10^(-19))

n = 3600*10^(19)/1.6

n = 2.25*10^(22)

So n = 2.25 * 10^(22) number of electrons is flowing through the wire

\_('_')"_/

Answer 2

$\huge\mathtt{\fbox{\red{Answer}}}$

Answer:

Using,

q = it

Where,

q is the charge flown in that wire in that given time!!

t is the time

i is the Current in Wire

So,

q = 0.5*(2*60*60)

q = 3600 C

Now Using Charge Quantization

q = ne

Where,

q is the magnitude of charge  

n is the number of electrons

e is the magnitude of electron

3600 = n*(1.6*10^(-19))

n = 3600*10^(19)/1.6

n = 2.25*10^(22)

So n = 2.25 * 10^(22) number of electrons is flowing through the wire