Question

If a current of 0.5 ampere flows through a metallic wire for two hours, then how many electrons flow through the wire?

Answer 1

Explanation:

given. I=0.5A

T=2hr=2*60*60seconds=7200s

since I=q/t

q=I*t = 0.5*7200

q=3600C

ne=3600C

n=3600/1.6*10^-19

n=225*10^19electrons

Answer 2

$\fbox{\texttt{\green{Answer:}}}$

No. of electrons = 2.246 × 10²²

$\fbox{\texttt{\pink{Given:}}}$

• Amount of current = 0.5 A
• Time = 2 hour

$\fbox{\texttt{\blue{To\:find:}}}$

No. of electrons that would flow through the wire.

$\fbox{\texttt{\red{How\:to\:Find:}}}$

Columbs of electrons = Current × time

= 0.5 A × 2 × 60 × 60 s

= 3600 C

Now. the current of 1F (96500 C) is equivalent to 1 mole i.e., 6.022 × 10²³ electrons.

∴ 3600 C of current is equivalent to flow of electrons

$\bold{=\:\dfrac{6.022\times{}10^{23}}{96500}\times{}3600}$

$\bold{=\:2.246\times{}10^{22}\:electrons.}$