Question

If a Current of 0.5 ampere flows through a metallic wire of 2 hours then hoe many electrons would flow through the wire ?

Answer 1

Answer:

2.25 × 10M²² electrons

Explanation:

Current, I = 0.5 A

Time, t = 2 hours

Convert in sec we get

Time, t = 2 × 60 × 60 s

= 7200 s

Use formula

Charge        Q = It

Put  the values we get

                      = 0.5 A × 7200 s

   = 3600 Coulombs

Number of electrons = total charge / charge on 1 electrons

                             = 3600/(1.6 ×1019)

                             =2.25 × 10M²² electrons  

Answer 2

Explanation:

$Charge(Q) = It$ -----(1)

$Chatge(Q)= ne$ ----(2)

$From \: eq.(1) \: and \: eq.(2)-$

$ne = It$

$\small\boxed{n \: = \: \frac{It}{e}}$

$where- \: n \: = no. \: of \: Electrons$

$I = current (In \: ampere)$

$t = time(in \: Second)$

$e = charge \: of \: an \: electrone$

$n = \frac{0.5 × 2 × 60 × 60}{1.6 × 10^{-19}}$

$n = \frac{1 × 3600}{1.6 × 10^{-19}}$

$n = \frac{3600 × 10^{19}}{1.6}$

$n = \frac{36 × 10^{21}}{1.6}$

$n = \frac{36 × 10^{22}}{16}$

$n = \frac{9 × 10^{22}}{4}$

$n = 2.25 × 10^{22} \: electrons$