Question

If a current of 0.6 ampere is passed through a wire having resistance 15 Ω for 2 minutes ,then the heat generated in the wire will be
a) 448 b) 548 c) 648 d) 448​

Answer 1

Answer:

648

Explanation:

As we know that,

Heat dissipated in a circuit is given by

H=I²Rt

In the question

I=0.6A

R=15 ohm

t= 2 min =2×60=120 s

Putting the above values in the given question...we get

H=(0.6)²×15×120

H=0.36×1800

H=648 J

Thank u ☺️

Answer 2

c) 648

$Heat \: =\: I^2rt \\\\\sf </p><p>= 0.6^2 x 15 x 120 \\\\\sf </p><p>= 0.36 x 15 x 120 \\\\\sf </p><p>= 648 J</p><p>$