Question

If a current of 2.5 ampere flows through a metallic wire for 2 hours then how many electrons would flow through the wire

Answer 1

hello...

I=Q/t

..

so...Q=I*t

= 2.5*3600*2

1 C carries 6.25*10^18 electrons

so... 2.5*7200 C carries =

$6.25 \times {10}^{18} \times 2.5 \times 7200$

electrons

so...no of electrons=

$11.25 \times {10}^{22}$

electrons

hope it helped....

plz mark brainliest

Answer 2

Given

current I = 2.5 Ampere

Time t = 2 hours = 2×3600 = 7200 s

We know charge Q = It

Q =2.5×7200  = 18000 C

Also 96487 C = 6.023 × 10²³ number of electrons.

Thus

18000 C will contain = (6.023 × 10²³× 18000)/96487 number of electrons.

= 1.12 × 10²³ number of electron will flow through the wire.