Physics, asked by ramjikamble0204, 5 hours ago

if a current of 2 ampere is drawn for one hour through the filament of a bulb find the amount of charge flowing through the circuit​

Answers

Answered by NewGeneEinstein
73

Answer:-

  • Current=I=2A
  • Time=1hour=3600s
  • Charge=Q=?

We know that.

\boxed{\sf I=\dfrac{Q}{t}}

\\ \sf\longmapsto Q=It

\\ \sf\longmapsto Q=2\times 3600

\\ \sf\longmapsto Q=7200C

Note:-

SI unit of charge is Coulomb (C)

Answered by rsagnik437
85

Answer :-

Amount of charge flowing through the circuit is 7200 Coulombs .

Explanation :-

We have :-

→ Current = 2 A

→ Time = 1 hour

________________________________

Firstly, let's convert the time taken from hour to sec .

⇒ 1 hour = (60 × 60) sec

⇒ 3600 sec

________________________________

Now, we know that

Q = It

Where :-

Q is charge .

I is current .

t is time .

⇒ Q = 2 × 3600

Q = 7200 C

Similar questions