Question

if a current of 3.2A per sec flows through a conducting wire calculate the no. of electros passing through it​

Answer 1

Answer:

Explanation:I=3.2A

t=1sec

I=Q/t

Q=IT

=3.2*1=3.2C

Total charge=3.2C

Charge of 1electron=1.6*10^-19C

No:of electrons=3.2%1.6*10^-19

=10^19*3.2%1.6

=2*10^19