Question

if a current of 5 A flows through the heater and the of heat produced is 54000 J in 6 minutes, then find the resistance of the electric heater ​

Answer 1

✪ Answer ✪

By formula, we know that $H=i^{2}Rt$

Here:

• H is the heat produced
• i is the current flowing through heater
• R is the resistance of the electric heater
• t is the time taken (In seconds)

Given :-

  H = 54000 J

  i = 5 A

  t = 6 min = 360 seconds

  R = ?

By substituting the values, we get :-

54000 = $5^{2}$ R (360)

R = 54000/9000

R = 6 Ω

Thus, resistance of the electric heater will be 6 Ω

Answer 2

Answer:

$\huge \tt{answer}$

Given-

R= ?

I = 5 ampere

H = 54000 J

t= 6 minutes

as we know,

1 minute= 60 seconds

therefore,

6 minutes= 360 seconds

by using formula of heat,

H = I²Rt

R= H / i²t

R = 54000/ 5×5×360

R = 54/9

therefore,

R= 6 ohm

here,

H= heat produced by heater

I = current of heater

R= resistance of heater

t= time

hope it is useful for you