Question

If a current of 5A flows through a resistor of 12 ohm then the power developed and the energy dissipated in 2 minutes are *

Answer 1

Explanation:

The heat generated is approximately equal to h=i^2*R*t

Here I= 5A

R=12 ohm

t= 60 sec

So h=25*12*60 =18000 joule =18 kJoule

Answer 2

Question

If a current of 5A flows through a resistor of 12 ohm then the power developed and the energy dissipated in 2 minutes are *

Answer:36000J

GIVEN

• I= 5A
• R=12 ohm
• t= 2minutes  =120sec

SOLUTION

The heat generated is approximately equal to h=i^2*R*t

So h=25*12*120 = 36000J