Question

if a current of 80 A flows for 10 seconds find the number of electrons. Answer is 5×10^18​

Answer 1

Answer:

Basic formula to calculate electrons is n = Q/e. e is electron charge which you know already. To determine Q use this I=Q/t which results Q=Ixt.

As you told, I=2A and t=1sec so Q will be Q=2x1= 2 Coloumb

Now n=2/1.6x10^-19 = 1.25x10^19

Hence total 1.25x10^19 electrons are flowing through a wire if 2A current is flowing for 1 sec.

Answer 2

l=q/t

q=l*t

i=80*10^-3

t=10s

q=8*10^-2*10

q=0.8coulombs

for 1c of charge there are 6.25*10^18

electrons

for 0.8c there are 0.8*6.25.*10^18

no. of electrons= 5*10^19

Explanation:

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