Question

if a cycle has front wheel of perimeter 66 and back wheel of 51.if front wheel revolves 2 21 times.how many revolutions will the back wheel take?​

Answer 1

Given,

The Perimeter of the Front Wheel= 66

Number of revolutions ( Front Wheel) = 221

The Perimeter of the Back Wheel= 51

To find,

No of revolutions ( Back Wheel)

Solution,

We know,

Distance traveled by front-wheel = Distance traveled by the back wheel.

i.e.,

221 ×66 = A × 51 ----------------(equation 1)

Since distance traveled is equal to the product of perimeter and number of revolutions made by one wheel. We have assumed the number of revolutions by the back wheel as A.

On solving equation 1 further,

A = (221 × 66) ÷ 51

A = 286

Hence, the number of revolutions made by the back wheel is 286.

Answer 2

Answer:

The number of revolutions taken by the back wheel is 286.

Step-by-step explanation:

Step 1

Given

A cycle has a front wheel of perimeter 66 and a back wheel of 51. If the front wheel revolves 2 21 times.

Distance traveled by the front wheel = distance traveled by the back wheel.

Let x be the number of revolutions taken by the back wheel.

221×66=A×51

Step 2

Solve the equation above and find the value of A.

14,586=A×51

A=$\frac{14,586}{51}$

A=286.

Hence, the number of revolutions taken by the back wheel is 286.