Math, asked by abhihoney030, 1 day ago

if a cyclic quadrilateral ABCD then angleA+ angle B=
ए साइक्लिक क्वाड्रीलेटरल एबीसीडी एंगल ए प्लस एंगल बी इज इक्वल टू

Answers

Answered by upharmishra3000

0

Step-by-step explanation:

(1 - sec(A) + tan A)/(1 + sec(A) - tan A) = (sec(A) + tan A - 1)/(sec(A) + tan A + 1)

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