Question

If A+D >C+E, C+D=2 B and B+E > C + D, it necessarily follows that​

Answer 1

Explanation:

⇒A+D>(2B−D)+E(∵C+D=2B)

⇒A+D>(B+E)+(B−D)

⇒A+D>(C+D)+(B−D)

⇒A+D>B+C.