Question

If a=d then find the ratio of Sn:tn

Answer 1

Answer:

lf first term a and common difference d are equal to each other then

we can calculate ratio of last term and sum of first n terms by using their formula and by putting a = d,as shown below

$t_n=a +( n - 1)d \\ a + (n - 1)a \\ = a - na - a \\ = na$

&

$S_n= \frac{a}{2} (2a + (n - 1)d) \\ = \frac{a}{2} (2a + (n - 1)a) \\ = \frac{a}{2} ((n + 1)a)$

NOW

$\frac{S_n}{t_n} = \frac{\frac{a}{2} ((n + 1)a)}{na} \\ = \frac{(n + 1)a}{2n}$

=(n+1)a:2n

Answer 2

Answer:

Step-by-step explanation:

Lets see

The solution