If A=diag(-1,-3,2), then |-2A| is equal to: *
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Given : A=diag(-1,-3,2)
To Find : |-2Al
Solution:
A=diag(-1,-3,2)
=> | A | = - 1 ( - 3 * 2 - 0)
= 6
| k A| = kⁿ| A| where n * n is order of matrix
Hence | - 2 A | = (-2)³ | A |
= - 8 * 6
= - 48
or
A=diag(-1,-3,2)
=> 2A = diag(-2,-6,4)
=> - 2A = diag(2,6,-4)
= 2 ( 6 * (- 4) - 0 )
= - 48
Hence |-2Al = -48
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