if a diameter of a circle bisects each other of the two chords of a circle , prove tht the chords are parallel..
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Answer:
ANSWER
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o Similarly, ∠CMO=90
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o Similarly, ∠CMO=90 o
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o Similarly, ∠CMO=90 o
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o Similarly, ∠CMO=90 o Therefore, ∠ALO=∠CMO
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o Similarly, ∠CMO=90 o Therefore, ∠ALO=∠CMOBut, these are corresponding angles.
ANSWERLet AB and CD be two chords of a circle whose centre is O, and let PQ be a diameter bisecting chords AB and CD at L and M respectively. Since PQ is a diameter. So, it passes through the centre O of the circle. Now,L is mid-point of AB.OL⊥AB [ Line joining the centre of a circle to the mid-point of a chord is perpendicular to the chord]∠ALO=90 o Similarly, ∠CMO=90 o Therefore, ∠ALO=∠CMOBut, these are corresponding angles.So, AB∥CD
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