Question

if a diameter of a circle is perpendicular to one of two parallel chords of the circle, prove that it is perpendicular to the other and bisects it.​

Answer 1

Answer:

Consider AB∥CD and POQ as the diameter

It is given that ∠PEB=90

o

From the figure, we know that AB∥CD and∠PED are corresponding angles

So we get

∠PFD=∠PEB

It can be written as

PF∠CD

In the same way

OF⊥CD

Perpendicular from the centre of a circle to a chord bisect the chord

So we get

CF=FD

Therefore it is proved that the diameter of a circle perpendicular to one of the two parallel chords of a circle is perpendicular to the other and bisects it.

Answer 2

Answer:

hi I am ӁJØKÊRӁӁJØKÊRӁӁJØKÊRӁ XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD XD