If a diametre of aroad roller is 0.9 m and its length is 1.4 m how much area od a field will be pressed in its 500 rotations
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answer = lateral surface area of a cylinder = 2*pie*r*h
radius = 0.9/2
= 0.45 m
height = 1.4 m
area = 2*22/7*0.45*1.4
= 2*22*0.2*0.45
1 rotation = 3.96 m²
500 rotations = 3.96*500
= 1980 m²
radius = 0.9/2
= 0.45 m
height = 1.4 m
area = 2*22/7*0.45*1.4
= 2*22*0.2*0.45
1 rotation = 3.96 m²
500 rotations = 3.96*500
= 1980 m²
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