Question

If a diatomic molecule has a dipole moment of 2.4 D and a bond distance of 1.2 A, then the fraction of electronic charge on each atom is

Answer 1

We have, δ = Dipole moment / d = (1.2 × 10–18 esu cm)/(1.0 × 10–8) cm \ = 1.2 × 10–10 esu.

Therefore, fraction of electronic charge on each end = (1.2 × 10–10)/(4.8 × 10–10), = 0.25 = 25%.

Hence the student apply the formula and get right solution get result for the given values with no risk and trouble of it.

Answer 2

$\huge \tt 25 \: \%$