if a dice is thrown at random what is a probability of getting 3,6,2,1
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total number of outcomes on a dice = 6
the numbers 3,6,2,1 occur only once on a dice.
thus, number of favourable outcomes= 4
hence, the probability of getting any one of these numbers at a throw is ;
= 4/6
= 2/3
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Total number of outcomes = 6
Total number of favourable outcomes =4(3,62,1,). P(E) = 4/6 = 2/3
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