Question

If a dice is thrown once ,there are two possible outcomes getting a number greater than 4 as less than equal to 4. Therefore probability of getting a number greater than 4 or less than equal to 4 . Find the probability of getting a number greater than 4. ​

Answer 1

Concept Understanding :-

• Probability is simply defined as the chance of occurring or not occuring of events.

• For a number, Probability lie between 0 to 1

0 stands for certain events and 1 is for impossible events. So you can say that it occuring between certain to impossible .

• In mathematical terms ,

Probability can be expressed as

Probability = Favourable outcome / Total outcome

Solution :-

Here,

In the question, It is mentioned that there is a dice which is thrown once .

So,

According to the question it has given that it has two possible outcomes of getting more than 4 or less than 4

Here,

We have to find the probability of getting greater than 4

Let's solve it,

Total outcomes of dice = 1 , 2 , 3 , 4 , 5 , 6 = 6

Favourable outcomes = 5 , 6 = 2

As we know that,

Probability = Favourable outcomes / total outcomes

Therefore,

Probability of getting greater number than 4

= 2 / 6 = 1 / 3

Hence, The probability of getting greater number than 4 is 1/3 $.$

Answer 2

$\huge \mathfrak \red{hello}$

$\huge \bf \green{answer}$

We know that sample space S on throwing a dice is S=(1,2,4,5,6)

∴ Total number of cases (possible outcomes) n(S)=6

Event E: Getting a number greater than 4,

E={5,6} Number of favourable gases=n(E)=2

Therefore ,P(E)=n(E)/n(S)=2/6=1/3

$\huge \sf \pink{therefore \: ur \: answer \: is \: \frac{1}{3} }$