Question

If a Dice is thrown Twice, then possibility of not getting 5 either times.
a) 1/3
b) 11/36
c) 25/36
d) both b and c​

Answer 1

Answer:

Step-by-step explanation:

Solution:

Total number of outcomes when die is thrown twice = 6 × 6 = 36.  

(i) Number of possible outcomes when 5 will come up either time = (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (1, 5), (2, 5), (3, 5), (4, 5), (6, 5) = 11

Probability that 5 will come up either time = Number of possible outcomes/Total number of favourable outcomes  

= 11/36

The probability that 5 will not come up either time = 1 - 11/36  

= 25/36

(ii) Number of possible outcomes when 5 will come up at least once = 11

The probability that 5 comes up at least once = Number of possible outcomes/Total number of favourable outcomes  

= 11/36

The probability that 5 will not come up either time is 25/36 and the probability that 5 will come up is 11/36.

Answer 2

Answer:

If a Dice is thrown Twice, then possibility of not getting 5 either times.

a) 1/3

b) 11/36

c) 25/36

d) both b and c

→b) 11/36