Question

If a dice is tossed the probability of its upper face bearing an odd number is

Answer 1

${\large{\mathfrak{\underline{\underline{\green{Solution \ :}}}}}}$



$\sf\green{Total \ outcomes \ = \ 6 \ \{ 1, 2, 3, 4, 5, 6 \} }$



$\sf\green{Favourable \ outcomes \ of \ getting \ an \ odd}$
$\sf\green{number \ = \ 3 \ \{ 1, 3, 5 \} }$



$\sf\green{P \ ( \ x \ ) \ = \ {\dfrac{Favourable \ outcomes}{Total \ outcomes}}}$



$\sf\green{P \ ( \ Getting \ an \ odd \ number \ ) \ = \ {\dfrac{3}{6}}}$



$\sf\green{P \ ( \ Getting \ an \ odd \ number \ ) \ = \ {\dfrac{1}{2}}}$



$\sf\green{P \ ( \ Getting \ an \ odd \ number \ ) \ = \ }$${\boxed{\sf{\green{0.5}}}}$



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