If a die is rolled 3 times what is the probability of getting at least one 6
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we can solve it by indirect method ::::
the probability of getting at least once 6 + not getting 6 = 1
since probability of not getting six in each throw = 5/6
in 3 three throws = 5*5*5/ 6*6*6
= 125/216
now probability of getting ateast one 6 = 1-125/216
= 91/216
91/216 will be ur answer...
I hope it will help u !!!
the probability of getting at least once 6 + not getting 6 = 1
since probability of not getting six in each throw = 5/6
in 3 three throws = 5*5*5/ 6*6*6
= 125/216
now probability of getting ateast one 6 = 1-125/216
= 91/216
91/216 will be ur answer...
I hope it will help u !!!
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