If a die is thrown twice. find the probability 1). 5 will come at least once. and 2). 5 will not come up either time
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Let A be the event of getting 5 at least once .. n(A) = 10 ... P(A) = n(A)÷ n(S) P(A) = 10 ÷ 36
So P(A) =0.36
Let B be the event that 5 will not come either time .. n(B) = 25 .. P(B) = 25 ÷ 36
In event A n ( A) = 11 Sorry for the mistake
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