If a die rolled once then the probability of obtaining a number greater than 3 is
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probability = no.favourable conditions ÷ no. of possible conditions.
no. of favourable conditions = 3. ( 4,5,6)
no. of possible conditions = 6.(1,2,3,4,5,6)
probability = 3÷6
therefore = 0.5 or 1 by 2.
no. of favourable conditions = 3. ( 4,5,6)
no. of possible conditions = 6.(1,2,3,4,5,6)
probability = 3÷6
therefore = 0.5 or 1 by 2.
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