if a digit chosen at random from the digits 1,2,3,4,5,6,7,8,9 then the probability that it is odd is? explain please
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27
The odd numbers out of these are= 1, 3, 5, 7, 9
No. of odd numbers = 5
The even numbers out of these are= 2, 4, 6, 8
No. of even numbers = 4
Total numbers = 9
So probability of choosing an odd number will be
= No. of odd numbers ÷ Total numbers
= 5 / 9
Similarly probability of choosing an even number will be
= No. of even numbers ÷ Total numbers
= 4 / 9
No. of odd numbers = 5
The even numbers out of these are= 2, 4, 6, 8
No. of even numbers = 4
Total numbers = 9
So probability of choosing an odd number will be
= No. of odd numbers ÷ Total numbers
= 5 / 9
Similarly probability of choosing an even number will be
= No. of even numbers ÷ Total numbers
= 4 / 9
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3
thanks it solves my question
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