If a digit is chosen at random from the digits 1,2,3,4,5,6,7,8,9, then the probability that it is odd, is *
Answers
Answered by
0
Answer:
5/9
Step-by-step explanation:
the sample space ={ 1,2,3,4,5,6,7,8,9}
total no of outcomes =9
no of favourable outcomes =5 (because we have 1,3,5,7,9)
probability =no of favourable outcomes/total no of outcomes
=5/9
PLS MARK ME AS THE BRAINLIEST
Answered by
2
» Answer :
The probability that the digits chosen is odd = 5 / 9
» Explanation :
S = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 }
Where S → Sample space
n ( S ) = 9
Let A be the event of getting odd numbers from the given digits.
A = { 1 , 3 , 5 , 7 , 9 }
n ( A ) = 5
Probability of A be ,
P ( A ) = n ( A ) / n ( S )
P ( A ) = 5 / 9
______________________
→ More info :
› A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from [ 0 , 1 ]
Where sample space is the total number of observations and the A is the Number of possible outcomes.
Similar questions