If a diverging lines is to be used to form an image which is one fourth of size of object where must the object be placed
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Answer:
Given : u=−0.5 m
Convex mirror forms erect image of real object.
Using,
h
o
h
i
=−
u
v
Or
4
1
=−
(−0.5)
v
⟹ v=0.125 m
Using mirror formula,
v
1
+
u
1
=
f
1
∴
0.125
1
+
−0.5
1
=
f
1
⟹ f=0.16 m
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