Question

If a driver drives at the rate of 32 km/h, he reaches his destination 7 minutes late. If he drives at the rate of 35 km/h he reaches 4 minutes earlier.
How far is his destination?


nooo spam...
​

Answer 1

Step-by-step explanation:

Let his destination be xkmphr

If he drives at the rate of 24kmphr, time taken by him=speeddistance=24x

Correct time=24x−605       ......(1)

If he drives at the rate of 30kmphr, time taken by him=30x

Correct time=30x+604       ......(2)

From (1) and (2)

24x−605=30x+604

⇒24x−30x=604+605

⇒1205x−4x=609

⇒x=20

Answer 2

Answer:

68.42km

Step-by-step explanation:

let destination = x km

let time taken normally = t minutes

according to question

=> x = 32(t+7)÷ 60....1

also

x = 35(t-4)÷60.......2

=> 32(t+7) ÷ 60 = 35(t-4) ÷ 60

=> 32t + 224 = 35t - 140

=> 35t-32t = 224+140

=> 3t = 364

=> t = 364/3

=> t = 121.3 minutes

x = 32(121.3+7)÷60

=> x = (32)(128.3)÷60

=> x = 68.42km