Question

if a =dt/b-t^2 where t represents the time A B are dimensional quantities then dimension of AB are..?​

Answer 1

Answer:

L.H.S=v

=[L][T^(-1)]

R.H.S=at+bt^2

[at]=[bt^2](since only quantity of same dimensions are additive.)

[bt^2]=[bT^2]

since LHS should be equal to RHS

so

[bT^2]=[LT^(-1)]

b=LT^(-3)

so dimension of b will be [LT^(-3)]

Explanation:

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