if a =dt/b-t^2 where t represents the time A B are dimensional quantities then dimension of AB are..?
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Answer:
L.H.S=v
=[L][T^(-1)]
R.H.S=at+bt^2
[at]=[bt^2](since only quantity of same dimensions are additive.)
[bt^2]=[bT^2]
since LHS should be equal to RHS so
[bT^2]=[LT^(-1)]
b=LT^(-3)
so dimension of b will be [LT^(-3)]
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