Question

if a =dt/b-t^2 where t represents the time A B are dimensional quantities then dimension of AB are..?​
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Answer 1

Given info : If a =dt/b-t^2 where t represents the time, A and B are dimensional quantities.

To find : the dimension of AB.

Solution : equation, you have written, very ambiguous.

I think, A = dt/(B - t²) , where dt is infinitesimal part of time. It is your correct equation. [ If not, write actual equation in comment, I will edit ]

Let's come to the point,

A = dt/(B - t²)

Dimension of dt = dimension of time = [T]

dimension of B = dimension of t² = [T]² = [T²]

So, dimension of A = dimension of dt/dimension of B = [T]/[T²] = [T¯¹]

Now dimension of AB = [T¯¹][T²] = [T]

Therefore the dimension of AB is [T] (i.e., dimension of time)

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Answer 2

Answer:

the correct answer is option number 3