if a equal 1650 and B equal 847 Express the HCF in a combination of linear equation
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Answer:
11= 19(1650) + (-37)847
Step-by-step explanation:
1650=2*3*5*5*11
847= 7*11*11
Therefore GCD = 11
By usual division we get the following
1650=1*847+803
847= 1*803+44
803 = 18*44+11
These equations can be written as
11= 803 - 18*44...........(1)
44= 847-1*803..........(2)
803=1650 - 1*847......(3)
Now,
11= 803 - 18*44
11= 803 - 18*(847-1*803) (using (2))
11= 803 - 18*847+18*803
11= - 18*847+19*803
11= - 18*847+19*(1650 - 1*847) (using (3))
11= - 18*847+19*1650 - 19*847
11= 19*1650 - 37*847
11= 19(1650) + (-37)847
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