Question

If a equal to minus 1 b equal to 3 and c is equal to minus 2 find the value of of following algebraic expressions a square b square minus 3 bc

Answer 1

Answer:

the answer is 63

Step-by-step explanation:

a=-1b=3

C=-2

a^2b^2 - 3bc = ?

on transposing - to the right side in 1 st equation..

a=-3 ; b=-3

substitute 'a' value in the given equation

(-3)^2 . (-3)^2 -- 3 (-3)(-2)

9×9 - [3×(-3)(-2)]

81-18=63

That is gonna be the final answer...