If a equal to minus 1 b equal to 3 and c is equal to minus 2 find the value of of following algebraic expressions a square b square minus 3 bc
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Answer:
the answer is 63
Step-by-step explanation:
a=-1b=3
C=-2
a^2b^2 - 3bc = ?
on transposing - to the right side in 1 st equation..
a=-3 ; b=-3
substitute 'a' value in the given equation
(-3)^2 . (-3)^2 -- 3 (-3)(-2)
9×9 - [3×(-3)(-2)]
81-18=63
That is gonna be the final answer...
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