if A exceeds B by 40%. and B is less than C by 20%, then A: C= ?
Answers
Answered by
102
Let C = 100
So B = 20% less than C or 80% of C = 80/100×100 = 80
And A exceeds B by 40%
So A = B + 40% of B
= 80 + 80 × 40/100 = 112
So A : C = A/C = 112/100 = 28/25
So B = 20% less than C or 80% of C = 80/100×100 = 80
And A exceeds B by 40%
So A = B + 40% of B
= 80 + 80 × 40/100 = 112
So A : C = A/C = 112/100 = 28/25
Answered by
22
A = B + 40% of B
A = 140/100 * B
Now,
A/B = 14/10
B = C - 20% of C
B = 80/100 *C
B/C = 8/10
SO,
A/C = (A/B) * (B/C) = (14 *8) / (10 *10) = 28 : 25.
Similar questions