If a factory manufactures 964 nut-bolts every day, what would be the number of nut-bolts manufactured in 30 days?
Estimate by rounding off the number of nut-bolts manufactured per day to the nearest thousand.
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Answer:
Let x be the no. of nuts & y be the bolts.
We have to maximize x & y if the factory worked at capacity of 12hours per day.
Clearly, x≥y,y≥0
Since we have only 12 hours of machine, we will use the following constraints:-
x+3y≤12
3x+y≤12
The profit of nuts is Rs.17.5 and bolts is Rs. 7 .
We need to maximize 17.5x+7y
We can see that the feasible region is bounded and in the first quadrant.
On solving the equations, x+3y=12 and 3x+y=12, we get x=3 and y=3.
Therefore, feasible points are (0,0);(0,4);(3,3);(4,4)
Values of z are(z=17.5x+7y)
The maximum profit =73.5 which is when 3 packets each of nuts & bolts are produced.
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