If'a fair coin is tossed 6 times find the probability of obtaining: (a) exactly 4 heads. (b) atleast 4 heads (c) atmost 2 heads
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(i) It is given that a coin is tossed 6 times Total number of outcomes = 26 = 64 Favourable outcomes of getting exactly 4 heads Probability of getting exactly 4 heads = Favourable outcomes/ Total number of outcomes = 15/64 (ii) It is given that a coin is tossed 6 times Total number of outcomes = 26 = 64 Favourable outcomes of getting at leats 1 head Probability of getting at least 1 head = Favourable outcomes/ Total number of outcomes = 63/64 (iii) It is given that a coin is tossed 6 times Total number of outcomes = 26 = 64 Favourable outcomes of getting at most 4 heads Probability of getting at most 4 heads = Favourable outcomes/ Total number of outcomes = 57/64Read more on Sarthaks.com - https://www.sarthaks.com/813768/coin-tossed-times-find-the-probability-getting-exactly-heads-least-head-iii-at-most-heads