if a fair dice is thrown twice, what is the probability of getting at least one six?
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Here is your answer buddy,
For two throws of a dice n(S) = 36
Let us consider an event A of getting number 6 on at least one dice.
A={(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)}
Number of outcomes of the event “atleast one six” = 11.
P(A) = 11/36
Hope this helps you.
Be Brainly.
For two throws of a dice n(S) = 36
Let us consider an event A of getting number 6 on at least one dice.
A={(1,6),(2,6),(3,6),(4,6),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5)}
Number of outcomes of the event “atleast one six” = 11.
P(A) = 11/36
Hope this helps you.
Be Brainly.
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