if a fir coin is tossed 10 times find the probability of exactly 6 heads,atleast 6 heads, atmost 6 heads
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N= number of heads in 10 tosses
Prob(N= x)= 10Cx × 1/2^N as we need x heads and N-x tails.
Prob(N>=6) = (10C6+ 10C7 + 10C8 + 10C9 + 1)* 1/2^10
= 386/1024
Prob(N=6)=10C6 × 1/2^10 = 210/1024
Prob(N<=6)= 1 - 386/1024. + 210/1024 = 848/1024
Prob(N= x)= 10Cx × 1/2^N as we need x heads and N-x tails.
Prob(N>=6) = (10C6+ 10C7 + 10C8 + 10C9 + 1)* 1/2^10
= 386/1024
Prob(N=6)=10C6 × 1/2^10 = 210/1024
Prob(N<=6)= 1 - 386/1024. + 210/1024 = 848/1024
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