If a flea can jump straight up to a height of 0,440m, what is its initial speed as it leaves the ground? How long is it in the air?
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v^2 = u^2 +2.a.s
where v = final velocity, u = initial velocity, a = acceleration (in this case, it’s g, -9.81m/s/s) and s = distance travelled.
Final velocity v at the top of the jump is zero.
Therefore 0 = u^2 + 2 x (-9.81) x 0.44
Therefore, rearranging: initial velocity u = square root(8.633) = 2.94m/s
Since v = u + a.t, time to max. height t = (v - u)/a
Therefore t = (-2.94)/(-9.81) = 0.3 seconds. Total time in the air is twice that as the flea has to fall to the ground again, i.e. total time in air = 0.6 seconds (neglecting air resistance)
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