Question

If a flywheel of mass 20 kg and diameter 1m is rotating 300 revolution per minute, its kinetic energy will be

Answer 1

Here you go!!!!!!!!!

Answer 2

The kinetic energy of the flywheel will be 1233.23 J.

Explanation:

Given that,

Mass of the flywheel, m = 20 kg

Diameter of the wheel, d = 1 m

Angular velocity of the flywheel, $\omega=300\ rev/min=31.41\ rad/s$

The rotational kinetic energy is given by :

$E=\dfrac{1}{2}I\omega^2$

I is the moment of inertia of flywheel, $I=\dfrac{mr^2}{2}$

$E=\dfrac{1}{4}mr^2\omega^2$

$E=\dfrac{1}{4}\times 20\times (0.5)^2\times (31.41)^2$

E = 1233.23 J

So, the kinetic energy of the flywheel will be 1233.23 J. Hence, this is the required solution.

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Rotational kinetic energy

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