Question

If a food seller bought one dozon of banana in Rs. 10 and sells 10 bananas of Rs 12 then what percentage profit or loss he gains?

in banglore it's Jayanagar​

Answer 1

Appropriate Question :-

If a food seller bought one dozen of banana in Rs. 10 and sells 10 bananas of Rs 12, then what percentage profit or loss, he get ?

$\large\underline{\sf{Solution-}}$

Given that,

• A food seller bought one dozen of banana in Rs. 10.

• He sells 10 bananas of Rs 12

It means,

• Cost price of 12 banana = Rs 10

• Selling Price of 10 banana = Rs 12

Thus,

$\sf Cost \: price \: of \: 1 \: banana \: = \: \dfrac{10}{12} = Rs \: \dfrac{5}{6}$

and

$\sf Selling \: price \: of \: 1 \: banana \: = \: \dfrac{12}{10} = Rs \: \dfrac{6}{5}$

Since, Selling Price > Cost Price

It implies, there is Profit in this transaction.

As we know,

$\sf Profit = Selling \: Price \: - \: Cost \: Price \:$

So, on substituting the values, we get

$\sf Profit = \dfrac{6}{5} \: - \: \dfrac{5}{6} \:$

$\sf Profit = \dfrac{36 - 25}{30} \:$

$\rm\implies \:\boxed{ \rm{ \:\sf Profit = Rs \: \dfrac{11}{30} \: \: }}$

Now, we know

$\sf Profit\% \: = \: \dfrac{Profit}{Cost \: Price} \times 100 \: \%$

$\sf Profit\% \: = \: \dfrac{\dfrac{11}{30} }{\dfrac{5}{6} } \times 100 \: \%$

$\sf Profit\% \: = \:\dfrac{11}{30} \times {\dfrac{6}{5} } \times 100 \: \%$

$\rm\implies \:\boxed{ \rm{ \:\sf Profit\% \: = \:44\: \% \: \: }}$

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Additional information :-

$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$

Answer 2

Correct question:

If a food seller bought one dozen of banana in Rs 10 and sells 10 bananas of Rs 12, then what percentage profit or loss, he get ?

To find:

The profit percentage or loss

Given:

• If a food seller bought one dozen of banana in Rs 10
• sells 10 bananas of Rs 12

Solution:

$\boxed{\mathsf{1 \ dozen=12}}$

Cost price:12 bananas cost 10rs

Selling price:10 bananas cost 12rs

So,The cost price of 1 banana=

$\to\mathtt{\frac{10}{12} rs}\\\\\to =\mathtt{\frac{5}{6} rs}$

So,The selling price of 1 banana=

$\to \mathtt{\frac{12}{10} rs}\\\\\to \mathstt{\frac{6}{5}rs}$

$\mathsf{Profit \ amount=Selling \ price-Cost \ price}$

So,Profit amount=

$\to \mathstt{\frac{6}{5} -\frac{5}{6}rs}\\\\\to = \mathtt{\frac{36-25}{30} rs}\\\\\to = \mathtt{\frac{11}{30} rs}$

As cost price of 1 banana is less than the selling price of 1 banana so,we are getting profit percentage

$\boxed{\mathsf{Profit \ percent=\frac{Profit \ amount}{Cost \ price} *100}}$

So,Profit percentage=

$\to \mathtt{\frac{\frac{11}{30} }{\frac{5}{6} } *100}$ %

$\to = \mathtt{40}$ %

Answer:

The profit percent=40%