Question

If a force exerted by a small sperical charged body on another object at 8cm is 2newton what will be the force exerted when the second object is moved to 4 cm

Answer 1

Like charges repel each other; unlike charges attract. ... The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

Answer 2

Given that,

A force exerted by a small spherical charged body on another object at 8 cm is 2 N.

To find,

The force exerted when the second object is moved to 4 cm.

Solution,

The force between charges is inversely proportional to the square of the distance such that,

$F\propto \dfrac{1}{r^2}$

So,

$\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}$

F₂ is force when distance is 4 cm.

$F_2=\dfrac{F_1r_1}{r_2}\\\\F_2=\dfrac{2\times 8}{4}\\\\F_2=4\ N$

So, force of 4 N is exerted when the second object is moved to 4 cm.

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