If a force of 10 N is exerted on an area of 500 square centimetre, the
magnitude of the pressure will be
Answers
Answer:
According To question
Force = 10N
Area = 500cm^2 = 500 × 10^-4 = 5 × 10^-2
Pressure = Force/Area
Pressure = 10/5 × 10^-2
pressure = 2 × 10^-2
Thanks
Answer:
The Correct Answer is 2×10² Pa. This means, if a force of 10 N is exerted on an area of 500 cm², the magnitude of exerted pressure will be 2×10² Pa.
Explanation:
Given: The applied force is 10 N and the area being 500 cm² .
To find: The magnitude of pressure applied.
Now, The force applied is 10 N.
Area being 500 cm². But as it is not in it's S.I. unit system, we will first change it into it's S.I. unit. We know that:
1 cm = 10⁻² m
Hence, 1 cm² = 10⁻⁴ m²
And therefore, 500 cm² = 500×10⁻⁴ m²
= 5×10⁻² m²
Now, we know that Pressure = Force applied ÷ Area
Therefore,
Pressure = 10 ÷ 5×10⁻²
= 2×10² Pa
Hence, the correct answer is 2×10² Pa.