Physics, asked by shreya29032002, 2 months ago

If a force of 10 N is exerted on an area of 500 square centimetre, the
magnitude of the pressure will be​

Answers

Answered by harsharora111
12

Answer:

According To question

Force = 10N

Area = 500cm^2 = 500 × 10^-4 = 5 × 10^-2

Pressure = Force/Area

Pressure = 10/5 × 10^-2

pressure = 2 × 10^-2

Thanks

Answered by varshika1664
0

Answer:

The Correct Answer is 2×10² Pa. This means, if a force of 10 N is exerted on an area of 500 cm², the magnitude of exerted pressure will be 2×10² Pa.

Explanation:

Given: The applied force is 10 N and the area being 500 cm² .

To find: The magnitude of pressure applied.

Now, The force applied is 10 N.

Area being 500 cm². But as it is not in it's S.I. unit system, we will first change it into it's S.I. unit. We know that:

1 cm = 10⁻² m

Hence, 1 cm² = 10⁻⁴ m²

And therefore, 500 cm² = 500×10⁻⁴ m²

                                        = 5×10⁻² m²

Now, we know that Pressure = Force applied ÷ Area

Therefore,

Pressure = 10 ÷ 5×10⁻²

               = 2×10² Pa

Hence, the correct answer is 2×10² Pa.

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