Question

if a force of 10 Newton acts on a body of mass 5 kg for one second then the rate of change of momentum​

Answer 1

Answer:

dP = 10 kg m/sec

Explanation:

given

Force = 10 N

time of action T = 1 sec

mas of body m = 5 kg

rate of change of momentum dP

according to newton second law

applied force = rate of change of momentum

F = dP/dT

10 = dP / 1

dP = 10 kg m/sec